To draw velocity diagram of slider crank mechanism
The crank of a slider crank mechanism rotates clockwise at a constant speed of 300 r.p.m. The crank is 150 mm and the connecting rod is 600 mm long. Determine : 1. Linear velocity and of the midpoint of the connecting rod, and 2. angular velocity of the connecting rod, at a crank angle of 45° from inner dead centre position.
P1A = 300 mm; P2B = 360 mm; AB = 360mm, and P1P2 = 600 mm. The angle AP1P2= 60°. The crank P 1A has an angular velocity of 10 rad/s and an angular acceleration of 30 rad/s 2, both clockwise. Determine the angular velocities of P2B, and AB and the velocity of the joint B.
PSolution:Given:N BO= 300 r.p.m. or ω BO= 2π × 300/60 = 31.42 rad/s; OB = 150 mm =0.15 m ; BA = 600 mm = 0.6m. We know that linear velocity of B with respect to O or velocity of B, v BO= v B= ω BO× O B= 31.42 × 0.15 = 4.713 m/s...(Perpendicular to B O)
Velocities in Slider Crank Mechanism
First of all draw the space diagram, to some suitable scale; as shown in Fig. Now the velocity diagram, as is drawn as discussed below:
The velocity diagram of slider crank was drawn and analysed.
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