To find the focal length of a concave lens using a convex lens.
between μ and v between 1/μ and 1/v
An optical bench with four uprights, a convex lens (less focal length), a concave lens (more focal length), two lens holder, two optical needles, a knitting needle & a half – metre scale.
From lens formula, we have:
ƒ = μv/μ-v
Actual length of knitting needle, x= 15 cm.
Observed distance between object needle & the lens when knitting needle is placed between them, y = 15 cm.
Observed distance between image needle & the lens when knitting needle is placed between them, z = 15 cm.
Index correction for μ = x – y = 0 cm
Index correction for v = x – z = 0 cm
S.No. | Position of cm/0 (cm)/L 1at O 1/I/L 2/I’ | μ=IL 2 | v= I’L2 | >ƒ = | ƒ=μv/μ-v | |||
1 | 29 | 50 | 75 | 69 | 78 | 6.0 | 9.0 | –18.0 |
2 | 27 | 50 | 71.5 | 65 | 77.5 | 6.5 | 12.5 | –13.54 |
3 | 25 | 50 | 70.5 | 65 | 72.8 | 5.5 | 7.8 | –18.64 |
4 | 28 | 50 | 71.3 | 63 | 71.2 | 8.3 | 8.2 | –17.45 |
Mean ƒ = ƒ1 + ƒ2 + ƒ3 + ƒ 4/4
= – 16.9 cm ≈ -17cm.
AB = AC = 2 ƒ or OC = OB = 2ƒ
The focal length of given concave lens = – 17 cm.
From 1/μ-1/v graph is, ƒ = 10.2 cm
Get all latest content delivered to your email a few times a month.