New York, NY IMG HI 58° LO 56° Home About Contact
IMG-LOGO
Home Chemistry Chemistry Class 12 Enthalpy of neutralization of strong acid and strong base
Chemistry Class 12 Lab Experiments

Enthalpy of neutralization of strong acid and strong base



Aim

To determine the enthalpy of neutralization of a strong acid (HCl) and a strong base (NaOH) using a pitch calorimeter in a laboratory setting.

Apparatus Required

  • Pitch calorimeter with lid and thermometer
  • 100 mL measuring cylinder
  • Stirrer
  • 1.0 M Hydrochloric acid (HCl)
  • 1.0 M Sodium hydroxide (NaOH)
  • Insulating material (cotton wool or cork)
  • Weighing balance
  • Thermometer (0-50°C)
  • Beakers (250 mL)

Theory

What is Enthalpy of Neutralization?

The enthalpy of neutralization is defined as the heat change when one gram equivalent of an acid is completely neutralized by a base in dilute solution at constant temperature.

For strong acids and strong bases like HCl and NaOH, the neutralization reaction can be represented as:

H⁺(aq) + OH⁻(aq) → H₂O(l)

The theoretical value of enthalpy of neutralization for strong acid-strong base combinations is approximately -57.1 kJ/mol.

Why is ΔH Constant for Strong Acid-Strong Base?

Strong acids and bases ionize completely in aqueous solution:

  • HCl → H⁺ + Cl⁻
  • NaOH → Na⁺ + OH⁻

The net ionic equation involves only H⁺ and OH⁻ ions, making the enthalpy change constant regardless of the specific strong acid or base used.

Procedure

  1. Preparation: Clean and dry the pitch calorimeter thoroughly.

  2. Initial Setup:

    • Note the initial temperature of the empty calorimeter
    • Take 50 mL of 1.0 M HCl in the calorimeter
    • Record the initial temperature of HCl (T₁)
  3. Base Preparation:

    • Take 50 mL of 1.0 M NaOH in a separate beaker
    • Record its temperature (T₂)
  4. Neutralization Process:

    • Quickly add NaOH to the calorimeter containing HCl
    • Stir the mixture continuously with the stirrer
    • Record the maximum temperature reached (T₃)
  5. Final Measurements:

    • Calculate the temperature change (ΔT)
    • Note the total volume of the solution

Observation Table

Parameter Reading
Volume of HCl taken 50 mL
Volume of NaOH taken 50 mL
Concentration of HCl 1.0 M
Concentration of NaOH 1.0 M
Initial temperature of HCl (T₁) ___°C
Initial temperature of NaOH (T₂) ___°C
Average initial temperature ___°C
Final temperature after mixing (T₃) ___°C
Temperature rise (ΔT = T₃ - Average initial temp) ___°C

Result

Calculations:

  1. Total volume of solution = 50 + 50 = 100 mL
  2. Mass of solution = 100 g (assuming density = 1 g/mL)
  3. Specific heat capacity (s) = 4.18 J/g°C
  4. Heat evolved (q) = m × s × ΔT = ___ J
  5. Number of moles of HCl/NaOH = 1.0 M × 0.05 L = 0.05 mol
  6. Enthalpy of neutralization (ΔH) = -q/n = ___ kJ/mol

The enthalpy of neutralization of HCl and NaOH is found to be __ kJ/mol.

Expected Result:

The experimental value should be close to the theoretical value of -57.1 kJ/mol.

Precautions

  1. Temperature Measurement: Read the thermometer carefully and avoid parallax error.

  2. Quick Mixing: Add NaOH to HCl quickly to minimize heat loss to surroundings.

  3. Insulation: Use insulating material around the calorimeter to prevent heat exchange.

  4. Stirring: Stir the solution continuously but gently to ensure uniform temperature.

  5. Safety: Handle HCl and NaOH carefully as they are corrosive substances.

  6. Calibration: Ensure the thermometer is properly calibrated before use.

  7. Volume Measurement: Use calibrated measuring cylinders for accurate volume measurement.

Viva Questions and Answers

Q1: What is the significance of using strong acid and strong base?

A: Strong acids and bases ionize completely, making the enthalpy change constant and predictable.

Q2: Why is the enthalpy of neutralization always negative?

A: The reaction is exothermic, releasing heat, hence the enthalpy change is negative.

Q3: What would happen if weak acid/weak base is used?

A: The enthalpy of neutralization would be less than -57.1 kJ/mol due to energy required for dissociation.

Q4: Why do we take equal volumes of acid and base?

A: To ensure complete neutralization and accurate stoichiometric calculations.

Q5: What is the role of the stirrer in the experiment?

A: It ensures uniform mixing and uniform temperature distribution throughout the solution.

Q6: How does_heat loss affect the result?

A: Heat loss to surroundings results in lower temperature rise, leading to lower calculated enthalpy value.

Q7: What is calorimetry?

A: Calorimetry is the science of measuring heat changes during chemical reactions.

Q8: Why is the theoretical value -57.1 kJ/mol?

A: This represents the heat evolved when one mole of water is formed from H⁺ and OH⁻ ions.

Conclusion

The pitch calorimeter method provides an effective way to determine the enthalpy of neutralization. The experimental value should closely match the theoretical value of -57.1 kJ/mol for strong acid-strong base neutralization. This experiment validates the principle that neutralization reactions between strong acids and bases have constant enthalpy changes due to complete ionization.









Chemistry Class 12 Lab Experiment list


Subscribe

Get all latest content delivered to your email a few times a month.