To determine the value of Stefan Boltzmann's constant.
Hemispherical enclosure diameter - 200 mm
Size of water jacket for hemisphere- 260 mm
Base Plate, hylum diameter - 240 mm
Test disc diameter - 20 mm
Specific heat of test disc (Cp)- 0.4168 kJ/kg K
No. of thermocouples mounted of enclosure - 4
No. of thermocouples mounted on the disc- 1
No. of thermocouples mounted water heater - 1
Immersion water heating capacity - 2000 watts
Mass of test disc - 0.008 kg
Temperature of hot water T1= 80°C
Sr. No | Temperature of hemispherical enclosure inner surface/T2(°C)/T3(°C)/T4(°C) |
Sr. No | Time (t) (Sec) | Temperature (T5) (°C) |
Emissive power (E) = σ ADT S4
Where,
AD = Area of the disc ‘D’ in m 2
TS = Average surface temp of Enclosure = T2+T3+T4in K/3
The radiant energy of the disc D, emitting into the enclosure ED is
ED = σ ADTD4 = σ AD(Tavg4-Td4)
Where,
TD = Temperature of disc T5in K
The net energy transferred to the disc
mcpdT/dt= σ AD(TD4 -Ts4)
Where,
m - Mass rate of test disc in kg
Cp - Specific heat of test disc in kJ/kg K
Stefan Boltzmann's Constant (σ) = m Cp(dT/dt)/AD(TD4 -Ts4) W/m2K4
Thus the Stefan Boltzmann's constant is determined as (σ) .............
The emissive power of a black body is proportional to fourth power of its absolute temperature & its constant’s value is 5.67x10-8 W/m2 K4
In radiation, internal energy of an object decreases.
It is defined as the total amount of radiation emitted by the body per unit time and unit area.
The energy emitted by the surface at a given length per unit time per unit area in all dimensions is known as monochromatic emissive power.
The heat transfer from one body to another without any transmitting medium is known as radiation
It is defined as the ability of the surface of a body to radiate the heat.
If a body absorbs a definite percentage of incident radiation irrespective of their wavelength, the body is known as Gray body.
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