Class 12 Physics Lab Experiments
To convert the given galvanometer (of known resistance & figure of merit) into an ammeter of desired range & to verify the same
May 28 2023
Aim
To convert the given galvanometer (of known resistance & figure of merit) into an ammeter of desired range & to verify the same.
Apparatus
A Weston type galvanometer whose resistance & figure of merit are given, a constantan or manganin wire, a battery, one-way key, a rheostat, a milli-ammeter, connecting wires, sand paper etc.
Formulae Used:
To convert a galvanometer which gives full scale deflection for current IGinto an ammeter of range O to IOamperes, the value of required shunt is given by: S= [I G/IO-I G]G
Required shunt resistant S is made using a uniform wire whose, specific resistance is σ (known) & its length:
ι=πr 2S/σ
Observation:
Given resistance of galvanometer, G = 70.8 Ω
Given value of figure of merit, k = 2.19 x 10 -5A div -1
Current for full scale deflection, IG= NOx k = 6.57 x 10 -4A
Calculation of value of shunt resistance:
*Required range of converted ammeter, IO= 3A
*Value of shunt resistance, S=[IG/IO-IG]x G=0.0155Ω
*Computing the length of the wire to make resistance of 0.155Ω
Observations for diameter of the wire:
Pitch of screw gauge, p = 1 mm
No. of division of circular scale = 100
Least count, a = 0.01 mm
Zero error, e = 0.0 mm
Diameter of the wire = 0.98 mm, Radius = 0.049 cm
Specific resistance of material of wire, ρ=1.92 x 10 -6Ω cm
Required length of the wire,cm
Required length of the wire,ι= S x π r/2/ σ=0.0155x3.14x(0.049)2/1.72 x 10 -6cm = 60.8cm
Table for Verification
S.No. |
Galvanometer Reading/Deflectionθ/Current I1=θ x LC |
Ammeter Reading I2 n x LC |
Error (I2-I1)A |
1 |
3 |
3x 0.1=0.3 |
6x 0.5=0.3 |
0.0 |
2 |
5 |
0.5 |
11 x 0.05=.55 |
0.05 |
3 |
7 |
0.7 |
15 x 0.05=.75 |
0.05 |
5 |
9 |
0.9 |
19 x 0.05=.95 |
0.05 |
Verification:
Checking the performance of the converted ammeter: Current indicated by full scale deflection (N O) of converted ammeter. I O= 3A
Least count of converted ammeter,k' = Io/No= 0.1A/div.
Result:
- Current IG for full scale deflection = 6.57 x 10 -4A
- Resistance of shunt required to convert the galvanometer into ammeter, S=0.0155Ω
- Required length of wire, ι=60.8 cm
- As error ι’–ι is very small, conversion is verified.
Precautions & Sources of Error:
- All connections should be neat & tight.
- The diameter of the wire for making shunt resistance should be measured accurately for diameter is taken in two mutually perpendicular directions.
- The terminal of the ammeter marked positive should be connected to positive pole of the battery. Also ammeter should be in series with circuit.
Mean k= 2.19 x 10 -5 A/div.
Result:
- Resistance of Galvanometer by half – deflection method: G= 70.8Ω
- Figure of merit, k= 2.19 x 10 -5 A/div.
Precautions & Sources of Error:
- All connections should be neat & tight.
- The diameter of the wire for making shunt resistance should be measured accurately for diameter is taken in two mutually perpendicular directions.
- Initially a high resistance from the resistance box (R) should be introduced in the circuit. Otherwise for small resistance, an excessive current will flow through the galvanometer or ammeter & damage them.
The terminal of the ammeter marked positive should be connected to positive pole of the battery. Also ammeter should be in series with circuit.