To determine unknown inductance of a given coil by Maxwell’s Bridge method.
S.No | Name | Type | Quantity |
1 | Maxwell’s Bridge training kit | EE-124 | 1 |
2 | Patch cords | - | 5-8 |
3 | Multimeter | Digital | 1 |
4 | Audio oscillator | 1 |
Impedance at audio and radio frequency is communally determined by means of an AC bridge known as Wheatstone bridge the schematics diagram is as shown as figure. This bridge is similar to the DC bridge (Used for measuring resistances) except that instead of being regarded as simple resistances The arms are now impedances which may have reactive component also the bridge is exceeded by alternating current rather than direct current and the Galvanometer is replaced by means such that as headphone for detecting alternating currents An AC bridge is balanced when the two junction across whom the null detector is connected are at the same potential at same instant of the AC cycle the current flow through the detector is zero. This will happen when the AC potential across point ‘ab’ and ‘ad’ have the same magnitude and are in phase and also those across ‘bc’ and ‘dc’.
The Maxwell’s Bridge is an a.c bridge, which is extensively used for the measurement of unknown inductance. It uses different combination of resistor, capacitor & inductor. Here it is assumed that the capacitor is loss less and resistor are purely non inductive In this we are using headphone as a detector and at the balance condition the junction across the detector have same potential .So the detector works as null detector through which the value of current is zero.
Circuit Diagram
Proof:According to the explanation of the AC bridges the bridge is balanced when two junctions across whom the null detector is connected are at the same potential at all instants of the AC cycles. So the current through the detector is zero this can be expressed mathematically as follows:
E ab= E ad
Z1I1 = Z4I2................................................(1)
&
E cb= E ed
Z2I1 = Z3I2................................................(2)
Divide Eq [1] by Eq . [2]
Z1I1/Z2I1=Z4I2/Z3I2
Z1Z3 = Z2Z4................................................(3)
This is balance condition. Where Z1, Z2, Z3 & Z4, are the impedances of the arms respectively and are vector, Complex quantities.
Z1, Z3= Z2, Z4
Where
Z1= R1/1+jwC1R1
Z2= R2
Z3= Rx+jwLx
Z4= R4
Substituting these values in Eq. [3] we get.
R1(Rx+jwLx)/1+jwC1R1=R2R4
∴R1Rx+jwLxRx=R2R4+jwC1R1R2R4
Separating the real & imaginary parts we get
R1Rx =R2R4
or LxR1 =R1R2C1R4
Lx=R2C1R4
Observation Table:
Selected value of R1 ………..
Selected value of C2……….
Selected value of R4 ………..
S.No | C1(In Farads) | R2(in Ohms) | Rx(in Ohms) | Practical value Lx=R2C1R4 | Standard Value Lx (in Henry) |
1 | |||||
2 | |||||
3 | |||||
4 | |||||
5 |
Conclusion:-The value of unknown inductance L xhas been calculated and when compared with standard values were found close to each other.
Viva-Voice Question:-
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