To Plot and study the characteristics of UJT & determine it’s intrinsic standoff Ratio.
S.No. | Name | Range | Type | Qty |
1 | R.P.S | (0-30)V | 2 | |
2 | Ammeter | (0–30)mA | 1 | |
3 | Voltmeter | (0–30)V/(0–10)V | 1 |
S.No. | Name | Range | Type | Qty |
1 | UJT | 2N2646 | 1 | |
2 | Resistor | 1KΩ | 2 | |
3 | Breadboard | 1 |
UJT(Double base diode) consists of a bar of lightly doped n-type silicon with a small piece of heavily doped P type material joined to one side. It has got three terminals. They are Emitter(E), Base1(B1),Base2(B2).Since the silicon bar is lightly doped, it has a high resistance & can be represented as two resistors, rB1& rB2. When VB1B2 = 0, a small increase in VE forward biases the emitter junction. The resultant plot of VE & IE is simply the characteristics of forward biased diode with resistance. Increasing VEB1 reduces the emitter junction reverse bias. When VEB1 = VrB1 there is no forward or reverse bias. & IE = 0. Increasing VEB1 beyond this point begins to forward bias the emitter junction. At the peak point, a small forward emitter current is flowing. This current is termed as peak current(IP). Until this point UJT is said to be operating in cutoff region. When I Eincreases beyond peak current the device enters the negative resistance region. In which the resistance rB1 falls rapidly & V E falls to the valley voltage.Vv. At this point I E= Iv. A further increase of I Ecauses the device to enter the saturation region.
Formula for Intrinsic Standoff Ratio:
η=V P-V D/ V B1B2, where V D= 0.7V.
Pin Diagram:
Specification for 2N2646:
* Inter base resistance R BBBB = 4.7 to 9.1 KΩ
* Minimum Valley current = 4 mA
* Maximun Peak point emitter current 5 μA
*Maximum emitter reverse current 12 μA.
Tabular Column:
V B1B2= 0V/V EB1(V)/I E(mA) | V B1B2= 10V/V EB1(V)/I E(mA) |
1 | |
2 | |
3 | |
4 | |
5 | |
6 | |
7 |
Get all latest content delivered to your email a few times a month.